Roulette System
This Roulette system is very easy for anyone to do and is pretty short to example. As usual, this Roulette system will play of the probability of action. We are only looking at even-money bets on the Roulette table, so that includes: odd and even, red and black and high and low. You could expand it out to the dozens and columns if desired, but that would require more modification than what will be presented. For this system, we are going to use a modified progression chain and it will contain four steps. Below is a chart that shows the steps for a $1 and $5 bettor.
| Bet Number |
$1 Bettor |
$5 Bettor |
| Bet Number One |
$1 |
$5 |
| Bet Number Two |
$3 |
$15 |
| Bet Number Three |
$7 |
$35 |
| Bet Number Four |
$16 |
$80 |
According to this betting pattern, the $1 bettor will need at least $27 for the progression chain and the $5 bettor will need $135. You will probably notice that this progression system is not a typical double up chain. The $1 bettor has four profit levels: $1, $2, $3, $5. The $5 bettor has four profit levels: $5, $10, $15, $25. Therefore, the deeper you get into the chain, the more profit you will have when you bet hits.
Losing
In the event that your chain gets busted, you do not continue on with bet five, six and so on. If you wish to continue, simply start over at bet number one again. Since the last bet would have been a consecutive loser, you will get right back on the horse and bet the same wager for the next spin. Here's a table that shows how you would play five consecutive ODD losses.
| Bet Number |
$1 Bettor |
Result |
| Bet Number One |
$1 |
Lost $1 |
| Bet Number Two |
$3 |
Lost $3 |
| Bet Number Three |
$7 |
Lost $7 |
| Bet Number Four |
$16 |
Lost $16 (busted) |
| Bet Number Five |
$1 |
Started Chain Again. |
While you might be tempted to at least double up for bet number five, it's not advised. Ok, let's talk about the system.
Roulette System
Each even-money bet has a 47.3% probability to show up on any spin in American Roulette and 48.6% in European Roulette. This equates to a 52.7% and a 51.4% probability of losing respectively.
The probability of losing four times consecutively, if you place the same bet, is 7.7% (American) and 6.9% (European). This is when the system starts. You will monitor the following outcomes: Odd and Even, Red and Black and High and Low. Once one of those comes up a certain way for four consecutive times, you bet the opposite. Pretty simple right?
On your first bet, you have a running winning probability of 96% (American) and 96.5% (European). Why? Well, the probability of an even-money bet winning five consecutive times is only 4% (American) and 3.5% (European). By waiting for four consecutive winners, you have dramatically increased your probability of winning.
However, because you have to wait for four consecutive winners, it can take a little time to reach that point. You are watching three separate bets and this will speed up the wait time. If you are on a fast table, or online, the wait time will be minimal.
That's all there is to the system. To give you an example, I am going to print out a quick listing of numbers from actual Roulette play.
Spins: 7,23,10,10,22,36
At this point, I can see that evens have come out four times in a row. Therefore, I now place my ODD bet. Next roll is: 9 red (winner).
Spins after winner: 5,20,21,7,24,11,14,1,5
At this point, I can see that LOW (1-18) has come out four consecutive times. I now place my bet on HIGH (19-36). The next roll is 12 RED. This means I need to step up to progression bet number two and bet black, because Reds have come out four consecutive times.
Next Roll: 10 Black (winner for Red/Black line). Loser on HIGH bet, so going to bet number three.
Next Roll: 11 Black. Loser on HIGH bet, so going to fourth and final bet.
Next Roll: 27 Red. Winner!
In the span of a handful of rolls, I have won three bets. Two came on the first roll. If I was a $5 player, I would be up $35.
Next time you are in a casino, look at the Roulette board (if they have one) and see how you would have done. |